# Line slope calculator 4x+5y=60

**Straight line given by points A[5; 8] and B[10; 4]**

## Calculation:

**Slope-intercept form of line:**y = -0.8x+12

**Canonical form of the line equation:**4x+5y-60 = 0

**Parametric form of the line equation:**

x = 5t+5

y = -4t+8 ; t ∈ R

**Slope:**m = -0.8

**Slope angle of line: φ =**-38°39'35″ = -0.6747 rad

**X intercept:**x

_{0}= 15

**Y intercept:**y

_{0}= q = 12

**Distance line from the origin:**d

_{0}= 9.3704

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; -4)

**Normal vector: n =**(4; 5)

**Midpoint of the segment AB: M =**[7.5; 6]

**Perpendicular Bisector equation:**5x-4y-13.5 = 0

**Vector OA = (5; 8) ; |OA| = 9.434**

**Vector OB = (10; 4) ; |OB| = 10.7703**

**Scalar product OA .OB = 82**

**Angle ∠ AOB = 36°11'36″ = 0.6317 rad**